Atomic No Of Fe



Write the electronic configuration of Fe(III) on the basis of crystal field theory when it forms an octahedral complex in the presence of (i) strong field, and (ii) weak field ligand. (Atomic no.of Fe=26)

Properties

Solution

Atomic

Atomic number of Fe is 26. That is, it has 26 electrons. Fe-1s2 2s2 2p6 3s2 3p6 3d6 4s2 Exactly when we dispose of one electron, Fe+ = 1s2 2s2 2p6 3s2 3p6 3d6 4s1. Atomic Spectroscopy, by W.C. Wiese in Atomic, Molecular, & Optical Physics Handbook, ed. Drake (AIP, Woodbury, NY, 1996) Chapter 10, pp. This website is also cited in the CRC Handbook as source of Section 1, subsection Electron Configuration of Neutral Atoms in the Ground State. 91 Pa: Rn 5f 2 (3 H 4) 6d 7s 2.

Table

`'Fe'= ['Ar']3'd'^6 4's'^2`

`'Fe'^{3+} = ['Ar']3'd'^6 4's'^2`

`'Fe'^(+3) = ['AR'] 3'd'^5 4's'^0`
In octahedral crystal field.
(i) Strong field ligand - Electrons will be paired.
No. of unpaired e- = 1
Paramagnetic
`μ = sqrt(n(n+2) = sqrt(1(3) = sqrt3 B.M`
(ii) Weak field ligand
- Electrons follow Hund’s rule
No. of unpaired = 5
Paramagnetic
`μ =sqrt(5(5+2))= sqrt(35) B.M.`

Concept: Bonding in Coordination Compounds - Crystal Field Theory (CFT)

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